#603 An airplane weighing 5000 lb strikes an upward

An airplane weighing 5000 lb strikes an upward - Mechanical Engineering

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Free Chegg Question

An airplane weighing 5000 lb strikes an upward gust of air which produces a wing lift of 25,000 lb (see Fig. P2.1) What lail load P is required to prevent a pitching acceleration if the dimensions are as shown? What will be the vertical acceleration of the airplane? if this lift force acts until the airplane obtains a vertical velocity of 20 ft/s, how much time is required?

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Free Chegg Answer

Apply the moment balance about the center of mass of the airplane

(The center of mass is where the weight acts)

Therefore we can write

25000*20 = P*200

P = 2500 lb

Now the acceleration is given by

a = 112.7 ft/s^2

From

V = U + at

20 = 0 + 112.7*t

t = 0.18 s