#250 A plant located at an altitude of

A plant is located at an altitude of - Mechanical Engineering

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Free Chegg Question

A plant is located at an altitude of 2500ft above sea level ( atmospheric pressure 27.5 in Hg). The open feedwater heater pump system is shown with the suction line equivalent length of 25 ft, pipe inside diameter of 3 in, and friction coefficient of 0.02. if the water flow rate is 180gpm and temperature is 190F, what is the available NPSH under this condition?

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Free Chegg Answer

As we know equation for Net positive suction head available is,

NPSH_A =  H_s - h_L + H_A - H_v

Where, Hs = Static suction head or lift, h_L= Suction line losses, H_A= Absolute pressure at the liquid free surface, H_v= Vapour pressure at liquid pumping temperature.

Given, H_S= +10 ft

         H_A= 27.5 inch of Hg = 31.16 ft of Water

(as 1 Inch of Mercury = 13 595.1 kg/m³ * 1 in * g & 1 Foot of Water = 999.972 kg/m³ * 1 ft * g)

H_v= Vapour pressure of water at 190 F= 9.327 psia= (9.327 * 2.31)/0.997 = 21.61 ft of water

Water flow rate (Q) = 180 gpm = 0.401 ft³/s ( as 1 ft³/s = 448.83 gpm)

So, velocity V = Q/A = 0.401/ (d² /4) = 0.401/(* 0.25²/4) = 8.17 ft/s

h_L = fLV²/ 2gd = 0.02 *25 * 8.17²/ 2 * 32.174* 0.25 = 2.074 ft

Hence, NPSH_A= +10 - 2.074 +31.16 - 21.61 = 17.475 ft