#402 The scores of 30 students on a test
The scores of 30 students on a test - Math
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The scores of 30 students on a test are shown below.
0 67 71 80 88
35 67 76 83 89
54 68 76 83 90
54 68 77 84 93
61 70 78 87 93
64 71 79 88 99
(a) Compute the five-number summary.
(b) Compute iqr and find outliers.
(c) Make a horizontal boxplot for this data showing outliers.
#7. For the sample data 14.8 12.7 18.0 14.5 12.3 10.5 9.1 8.3
(a) Compute the sample mean , sample median .
(b) Are the two measures similar? What does it imply regarding the shape of the distribution?
#8. For the sample data 6.5 12.0 14.9 10.0
(a) Compute the mean and median
(b) What would you report as a representative, or typical value, and what prompted your choice?
(c) Compute the standard deviation and iqr.
(d) What would you report as a measure of dispersion, the standard deviation or the iqr? Explain why.
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rank | |
0 | 1 |
35 | 2 |
54 | 3 |
54 | 4 |
61 | 5 |
64 | 6 |
67 | 7 |
67 | 8 |
68 | 9 |
68 | 10 |
70 | 11 |
71 | 12 |
71 | 13 |
76 | 14 |
76 | 15 |
77 | 16 |
78 | 17 |
79 | 18 |
80 | 19 |
83 | 20 |
83 | 21 |
84 | 22 |
87 | 23 |
88 | 24 |
88 | 25 |
89 | 26 |
90 | 27 |
93 | 28 |
93 | 29 |
99 | 30 |
A)1.Minimum = 0
2.
Q1=(1/4)30=(1/4)x30=7.5=8th term=67
Q1=67
3.Median =((n/2 th term+((n/2)+1) term)/2
=(15th+16th term)/2
=(76+77)/2
= 76.5
4. Q3=(3/4)30=22.5 = 23rd term= 87
Q3=87
5. Maximum =99
B)IQR = Q3- Q1=87-67=20
Lower inner fence=Q1-1.5*IQ=67-(1.5*20)=
Upper inner fence=Q3+1.5*IQ=87+1.5*20=117
Lower outer fence=Q1-3*IQ=67-3*20=7
Upper outer fence =Q3+3*IQ=87+3*20=147
From an examination of the fence points and the data , one point 0 exceeds the lower outer fence , there are 1 extreme outlier
C)
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