#336 A roller-coaster car has a mass

A roller-coaster car has a mass - Physics

ChemistryExplain daily providing Q&A content “#336 A roller-coaster car has a mass" in Physics, Ap physics 1 practice test, Best colleges for physics, Best physics books, Best physics schools

Get the Free Online Chemistry Q&A Questions And Answers with explain. To crack any examinations and Interview tests these Chemistry Questions And Answers are very useful. Here we have uploaded the Free Online Chemistry Questions. Here we are also given the all chemistry topic.

 ChemistryExplain team has covered all Topics related to inorganic, organic, physical chemistry, and others So, Prepare these Chemistry Questions and Answers with Explanation Pdf.

For More Chegg Questions

• Inorganic Chemistry
• Organic Chemistry
• Physical Chemistry

Free Chegg Question

A roller-coaster car has a mass of 504 kg when fully loaded with passengers. The path of the coaster from its initial point shown in the figure to point B involves only up-and-down motion (as seen by the riders), with no motion to the left or right. Assume the roller- coaster tracks at points are parts of vertical circles of radius r1 10.0 m and r2 = 15.0 m, respectively.

For More Chemistry Notes and Helpful Content Subscribe Our YouTube Chanel - Chemistry Explain  

Free Chegg Answer

Mass of the car = 504 kg

Radious r₁ = 10 m

Radious r₂ = 15 m

a) Speed of car at point A = 20.7 m/s

At point A, since car is moving in a circle it requires a centripital force F_c upward.

Where F_c = mv²/r

If the ground reaction is R then forces acting  on car are

i) Force due to gravity = mg down ward

iii) Rection force = R

As the acceleration is upward the forces are balanced by following equation:

F_c = R-Mg

or mv²/r = R-Mg

so R = Mg + Mv²/r  

= 504 X 9.8 + 504 X 20.7 ² / 10 = 26535 N

R = 26535 N

Therefore at point A, force exerted by ground on car = 26535

b) At point B car will have centrpital acceleration in the downward direction. Therefore

- Mv²/r = R-Mg

so Mv²/r = Mg - R  

For maximum value of speed R will be zero (R can not be negative)

So maximum speed =  ( g X r)

In above equation , r = 15 m, R=0 (For maximum speed)

So maximum speed v =  ( g X r) =   ( 9.8 X 15) = 12.12 m/s