Friday, October 2, 2020

#319 The following data were obtained from

The following data were obtained from - Civil Engineering

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ChemistryExplain “#319 The following data were obtained from in Mechanical Engineering, Best colleges for mechanical engineering, Entry level mechanical
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The following data were obtained from the tensile test of Aluminum alloy. The initial diameter of test specimen was 0.505 inch and gauge length was 2.0 inch. Plot the stress strain diagram and determine (a) Proportional Limit (b) Modulus of Elasticity (c) Yield Stress at 0.2% offset (d) Ultimate Stress and (e) Nominal Rupture Stress.

ChemistryExplain “#319 The following data were obtained from in Mechanical Engineering, Best colleges for mechanical engineering, Entry level mechanical

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GIVEN THAT,

INITIAL DIAMETER OF SPECIMEN= D=0.505inch

LENGTH OF SPECIMEN = L= 2.0inch

therefore,

AREA OF SPECIMEN=2 πR2 + (2πRL)

WHERE RADIUS R=D/2=0.505/2=0.2525inch

AREA= A= 2X3.14X0.25252+2X3.14X0.2525X2.0

A =3.573 inch2

AS WE KNOW THAT, STRESS = LAOD/ AREA

AND STRAIN = CHANGE IN LENGTH/ ORIGINAL LENGTH

THE FOLLOWING VALUES ARE STRESS AND STRAIN CALCULATED FROM ABOVE FORMULAS

ChemistryExplain “#319 The following data were obtained from in Mechanical Engineering, Best colleges for mechanical engineering, Entry level mechanical

a) PROPORTIONAL LIMIT:NOW THE STRESS STRAIN DIAGRAM IS:

ChemistryExplain “#319 The following data were obtained from in Mechanical Engineering, Best colleges for mechanical engineering, Entry level mechanical

IT IS THE GREATEST STRESS THAT IS DIRECTLY PROPORTIONAL TO STRAIN.

FROM THE CURVE THE PROPORTIONAL LIMIT=3246lb/inch2

b) MODULUS OF ELASTICITY = IT IS GRADIENT OF STRESS STRAIN CURVE

=3246/0.0055=341lb/ft3

c) YIELD STRESS AT 0.2% OFFSET:

IT IS OBTAINED BY DRAWING A LINE PARREL TO INITIAL LINEAR LINE OF STRESS STRAIN CURVE AND TAKING THE PEAKEST POINT ON CURVE WHERE THIS PARALLEL LINE MEEETS. THIS LINE GENERALLY DRAWN FROM 0.002 STRAIN.

YIELD STRESS= 4000lb/inch2

d) ULTIMATE STRESS = 4142.17lb/inch2

e) NOMINAL RUPTURE STRESS = SRESS AT FRACUTE =3806.32llb/inch2

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