#150 In the lecture unit1, we implement the concept of waiting
In the lecture (unit1), we implement the concept of waiting - Computer Science
ChemistryExplain daily providing Q&A content “#150 In the lecture (unit1), we implement the concept of waiting" in Computer science, Ba computer science, Berkeley computer science, Computer science associate degree jobsGet the Free Online Chemistry Q&A Questions And Answers with explain. To crack any examinations and Interview tests these Chemistry Questions And Answers are very useful. Here we have uploaded the Free Online Chemistry Questions. Here we are also given the all chemistry topic.
ChemistryExplain team has covered all Topics related to inorganic, organic, physical chemistry, and others So, Prepare these Chemistry Questions and Answers with Explanation Pdf.
For More Chegg Questions
Free Chegg Question
In the lecture (unit1), we implement the concept of waiting list of generic type using an array.1- Now, we want to implement the concept (as generic ) using ArrayList. Your generic WaitingList
class should include the following method:
-
a- add: it receives generic type elements and add it to the end of the list.
-
b- get: it receives an index and returns the element at the specific index (if there is ), or null if
there is no such index.
-
c- remove: it removes the first element, and returns that element.
-
d- print: it prints the elements in the waiting list.
Create class GC_Test, that has main method. In the main,
-
a- Create WaitingList of Car, and add three cars.
-
b- Test method remove, reverse , and print the list after each method to test the methods.
-
c- Create WaitingList of Student, and add four students.
- d- Test method remove, reverse , and print the list after each method to test the methods.
Free Chegg Answer
public class MaximumTest { // determines the largest of three Comparable objects public static <T extends Comparable<T>> T maximum(T x, T y, T z) { T max = x; // assume x is initially the largest if(y.compareTo(max) > 0) { max = y; // y is the largest so far } if(z.compareTo(max) > 0) { max = z; // z is the largest now } return max; // returns the largest object } public static void main(String args[]) { System.out.printf("Max of %d, %d and %d is %d\n\n", 3, 4, 5, maximum( 3, 4, 5 )); System.out.printf("Max of %.1f,%.1f and %.1f is %.1f\n\n", 6.6, 8.8, 7.7, maximum( 6.6, 8.8, 7.7 )); System.out.printf("Max of %s, %s and %s is %s\n","pear", "apple", "orange", maximum("pear", "apple", "orange")); } }
Labels: Chegg, Free Chegg Answer, Q&A Computer Science
0 Comments:
Post a Comment
Subscribe to Post Comments [Atom]
<< Home