#68 The track for this racing event was designed

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Question

#68 The track for this racing event was designed so that riders jump off the slope at 30^degree, from a height of 1 m. During a race, it was observed that the rider shown in Fig. 12-23_alpha remained in midair for 1.5 s. Determine the speed at which he was traveling off the slope, the horizontal distance he travels before striking the ground, and the maximum height he attains. Neglect the size of the bike and rider.

Answer

using 2nd equation of motion

h = ho + u sin x * t - 0.5 gt^2

0 = 1 + u * sin 30 * 1.5 - 4.9* 1.5^2

u = 13.367 m/s

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horizontal range

R = u cos x * t = 13.367* cos 30* 1.5 = 17.364 m

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vertical max height

H = 1 + ( u sin x)^2/ 2g

H = 1 + 13.367^2 / ( 19.6)

H = 3.28 m